How did you get 3/200?
1 >1 >2 >3 >42 >1 >2 >3 >4Chance to get 1 or 2 is 3/100, so imagine u get 1, u now need a 2 (which is the same % as 1) so the first 100 are from the 1 to 4, and the second 100 are from the 1 to 4 within the first run (which was 1).So basicly, the chance to get two 1>1, 1>2, 2>1 or 2>2 are all 3/200. (Not talking about together, together the chance is 3/200 x 4)
Each run is independent from each other. What you got in your previous run does not affect what you will get this run.
No how i see it. I was calculating the chance to get both, not just one.