There is no positive way of answering this fully correctly. Just because there is that 50% chance to have a critical attack, does not mean every other attack will necessarily be a critical strike.If you were to flip a coin 10 times, sure you have a 50% chance to get Heads or Tails, but there is still a chance that you may end up getting more heads than tails, or vice-versa.
Let E(m) be the expected amount of hits remaining to reach n starting at a sum of mE(n) = 0E(n-1) = 1E(n-x) = (1/2)*(1+E(x-1)) + (1/2) * (1+E(x-2))The answer you asked for is the case E(n-10).As I'm a programmer and not a mathematician Ill have my computer do the hard work from here telling me that the final result is approximately 6.888 hits.Also, you made me do math before I've had coffee, you monster.
Haha, I just wanted to skip the writing it out further, way too much work. Also I'm sure it could, computers are pretty good at computing stuff.
answer part 2:3-4 crits on averageP.S dunt ask how i get the answer, and i hate writing on decimals :c
Lol...You provided the range where the correct answer falls in. But an average number is not a range.
This is the question for Part 2:Assuming you deal 1 damage to a monster every time when u attack, your accuracy is always 100%, your critical rate is 50%, and you deal 2 damage when you deal a critical hit. If the monster has 10 hp, how many critical hits will occur on average until you kill the monster?
No one read a question. "how many critical hits will occur on average until you kill the monster"its required number of crit hits do not count non crit hits
if u referring to me, i read the question sir. if u not then i apologize