# How many of you can get this right? (Part 2)

#### アイドンノウくん

• Old Player
This is the question for Part 2:

Assuming you deal 1 damage to a monster every time when u attack, your accuracy is always 100%, your critical rate is 50%, and you deal 2 damage when you deal a critical hit. If the monster has 10 hp, how many critical hits will occur on average until you kill the monster?

Somebody has got it right. (See reply #36)

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This is the question for Part 1:

Assuming you deal 1 damage to a monster every time when u attack, your accuracy is always 100%, your critical rate is 50%, and you deal 2 damage when you deal a critical hit. If the monster has 10 hp, how many hits do you need on average to kill the monster?

Also, someone has got it right (see reply #14).
Last Edit: Feb 28, 2014, 08:50 pm by IDuKnow

#### SQUISHY BARB

• Member
• Characters: SQUlSHY
SQUlSHY - Sage DPH Barb White Panda
__SQUISHY__ - Demon Mystic - alt

#### Flavor

• Tenshi
• <3Jan
• Characters: PearlieKyun
Every 2 hits = 3 damage
10/3= 3.33
3.33 x 2= 6.66.
So 7 hits needed.

• LF friends D:
• Coooooookieees
omg wtf is this math about PW how dare you bring math here

this cant be allowed

watch for info:

#### アイドンノウくん

• Old Player
7 hits ?
Did you get a number and round it to 7? If so, what was the number before rounding?

If you got 7 exactly, then you did not get the correct answer.

#### アイドンノウくん

• Old Player
Every 2 hits = 3 damage
10/3= 3.33
3.33 x 2= 6.66.
So 7 hits needed.
Unfortunately, before you rounded it to 7, it was already wrong. Good try though!

#### アイドンノウくん

• Old Player
omg wtf is this math about PW how dare you bring math here

this cant be allowed
I just find it interesting and would like to see how many people here can get it right.

#### SQUISHY BARB

• Member
• Characters: SQUlSHY
Did you get a number and round it to 7? If so, what was the number before rounding?

If you got 7 exactly, then you did not get the correct answer.

i hate math.

i just counted with my fingers.
alternated normal hit and crit. like

1212121 = 7 hits
2121212 = 7 hits

depending on whether i get lucky or not. i may or may not crit that much since .50% crit rate won't guarantee that i will get one every other hit. i could hit more than ten without critting or get consecutive crits as well.  this is all confusing to be honest, too much for my brain. >.<
SQUlSHY - Sage DPH Barb White Panda
__SQUISHY__ - Demon Mystic - alt

#### アイドンノウくん

• Old Player

i hate math.

i just counted with my fingers.
alternated normal hit and crit. like

1212121 = 7 hits
2121212 = 7 hits

depending on whether i get lucky or not. i may or may not crit that much since .50% crit rate won't guarantee that i will get one every other hit. i could hit more than ten without critting or get consecutive crits as well.  this is all confusing to be honest, too much for my brain. >.<
I like your approach, but it does not give you the average number. I suspect that you chose 7 because it has the highest number of combination. However, it is not the average number of hit. But the good thing is somehow you got the mode right.

#### Chum

• Fail Barb
• Characters: Chum, Swampy
10, because percentages are bullshit and hate me.

#### Broobndoobn

• Old Player
There is no positive way of answering this fully correctly. Just because there is that 50% chance to have a critical attack, does not mean every other attack will necessarily be a critical strike.

If you were to flip a coin 10 times, sure you have a 50% chance to get Heads or Tails, but there is still a chance that you may end up getting more heads than tails, or vice-versa.

#### Steroids

• God of Noobs
• Faction: Rawr
There is no correct answer for this. Crit rate trolls me all the time.

#### Vegas

10 with my luck

• LF friends D:
• Coooooookieees
OMG YOU BECOME FRIENDS WITH MONSTER AND NOBODY HAS TO BE KILLED!

AWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWW
watch for info:

#### Feone

• Forum Veteran
Let E(m) be the expected amount of hits remaining to reach n starting at a sum of m

E(n) = 0
E(n-1) = 1
E(n-x) = (1/2)*(1+E(x-1)) + (1/2) * (1+E(x-2))